[백준 Java] 2480: 주사위 세개

1. 문제

2. 맞춘코드

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.IOException;
import java.util.StringTokenizer;

public class bj2480{
	public static void main(String[] args) throws IOException {
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		StringTokenizer st = new StringTokenizer(br.readLine()," ");

		int a, b, c, total=0;

		a = Integer.parseInt(st.nextToken());
		b = Integer.parseInt(st.nextToken());
		c = Integer.parseInt(st.nextToken());

		// 큰수대로 오름차순
		if(a>b){
			a=a^b;
			b=b^a;
			a=a^b;
		}
		if(a>c){
			a=a^c;
			c=c^a;
			a=a^c;
		}
		if(b>c){
			b=b^c;
			c=c^b;
			b=b^c;
		}

		if(a == b && a == c)	// 3개 같은 눈
			total=10000+c*1000;
		else if((a == b && a != c) || (c == a && b != c)){	// 2개 같은 눈-a
			total=1000+a*100;			
		}
		else if(b == c && a != c){	// 2개 같은 눈-b
			total=1000+b*100;			
		}
		else{
			total=c*100;
		}

		System.out.printf("%d", total);
	}
}